Create a function that takes a number n and checks if each digit is divisible by the digit on its left. Return a boolean array depending on the condition checks.
divisible_by_left(73312) β [False, False, True, False, True]
# no element left to 7 = False
# 3/7 = False
# 3/3 = True
# 1/3 = False
# 2/1 = True
divisible_by_left(1) β [False]
divisible_by_left(635) β [False, False, False]
The array should always start with False as there is no digit to the left of the first digit.