The goal of this challenge is to return Pascal's triangle up to number 29. Pascal's triangle is the sum of the two upper corners.
1 1
1 2 1
1 3 3 1
// There will always be the 1 in the first
// place and the row in the second.

Create a function that returns a row from Pascal's triangle. To find the row and column you can use n!/(k!*(n-k)!) where n is the row down and k is the column.
pascalsTriangle(1) ➞ "1 1"
pascalsTriangle(4) ➞ "1 4 6 4 1"
pascalsTriangle(6) ➞ "1 6 15 20 15 6 1"
pascalsTriangle(8) ➞ "1 8 28 56 70 56 28 8 1"
N/A