A number n becomes a super-d number when, for any digit d from 2 up to 9, the result of d * nᵈ contains d consecutive digits equal to d.
Given a positive integer n, implement a function that returns:
"Super-d Number" if n is a super-d number, replacing the letterd with the digit (any from 2 up to 9) that makes it super;"Normal Number" if n is not a super-d number.isSuperD(19) ➞ "Super-2 Number"
// when d = 2
// 2 * 19² = 722
// There are two (d) consecutives digits equal to 2 (d)
isSuperD(753) ➞ "Super-3 Number"
// when d = 3
// 3 * 753³ = 1280873331
// There are three (d) consecutives digits equal to 3 (d)
isSuperD(1168) ➞ "Super-4 Number"
// when d = 4
// 4 * 1168⁴ = 7444428488704
// There are four (d) consecutives digits equal to 4 (d)
isSuperD(24) ➞ "Normal Number"
// No cases where d * 24ᵈ (with d being any digit from 2 up to 9)...
// ...leads to a result containing d consecutive digits equal to d
n will be a positive integer greater or equal to 0.