In this challenge, you have to establish if an integer num is Alternating. To be Alternating, num must be positive and every digit in its sequence must have a different parity than its next and its previous digit.
Given an integer num, implement a function that returns true is num is an Alternating number, or false if it's not.
isAlternating(123) ➞ true
// 1 is odd, 2 is even, 3 is odd
isAlternating(67) ➞ true
// 6 is even, 7 is odd
isAlternating(2380) ➞ false
// 2 is even, 3 is odd, 8 is even, 0 is even
isAlternating(75) ➞ false
// 7 is odd, 5 is odd
false.