Fix the Error: Value vs. Reference Types

Create a function that returns True if two lists contain identical values, and False otherwise.

To solve this question, your friend writes the following code:

def check_equals(lst1, lst2):
    if lst1 is lst2:
        return True
    else:
        return False

But testing the code, you see that something is not quite right. Running the code yields the following results:

check_equals([1, 2], [1, 3]) ➞ False
# Good so far...

check_equals([1, 2], [1, 2]) ➞ False
# Yikes! What happened?

Rewrite your friend's code so that it correctly checks if two lists are equal. To be equal, the lists must have the same elements in the same order. The tests below should pass:

Examples

check_equals([1, 2], [1, 3]) ➞ False

check_equals([1, 2], [1, 2]) ➞ True

check_equals([4, 5, 6], [4, 5, 6]) ➞ True

check_equals([4, 7, 6], [4, 5, 6]) ➞ False

Notes

Hint: This has to do with value vs. reference types.