Find the Bug: Checking Even Numbers

Create a function that takes in an array and returns true if all its values are even, and false otherwise.

Not a big deal, your friend says. He writes the following code:

function checkAllEven(arr) {
  return arr.every(x % 2 === 0)
}

The code above leads to a Reference Error, with x being undefined. Fix the code above so that all tests pass:

Examples

checkAllEven([1, 2, 3, 4]) ➞ false

checkAllEven([2, 4, 6]) ➞ true

checkAllEven([5, 6, 8, 10]) ➞ false

checkAllEven([-2, 2, -2, 2]) ➞ true

Notes