Group in Order

Create a function that groups a list of numbers based on a size parameter. The size represents the maximum length of each sub-list.

[1, 2, 3, 4, 5, 6], 3
[[1, 3, 5], [2, 4, 6]]
# Divide list into groups of size 3.

[1, 2, 3, 4, 5, 6], 2
[[1, 4], [2, 5], [3, 6]]
# Divide list into groups of size 2.

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11], 4
[[1, 4, 7, 10], [2, 5, 8, 11], [3, 6, 9]]
# "Leftover" lists are okay.

Examples

group([1, 2, 3, 4], 2) ➞ [[1, 3], [2, 4]]

group([1, 2, 3, 4, 5, 6, 7], 4) ➞ [[1, 3, 5, 7], [2, 4, 6]]

group([1, 2, 3, 4, 5], 1) ➞ [[1], [2], [3], [4], [5]]

group([1, 2, 3, 4, 5, 6], 4) ➞ [[1, 3, 5], [2, 4, 6]]

Notes

• The size parameter represents the maximum size for each sub-list (see ex.4). You should try to fill each sub-list evenly. In other words, ex.4 should be [[1, 3, 5], [2, 4, 6]], not [[1, 3, 5, 6], [2, 4]].
• Keep the relative order of the numbers in each sub-list the same as the order in the original list.
• When distributing the numbers into the sub-lists, each sub-list should have a number in it prior to receiving a new number (e.g. for example 1, your sub-lists will be of size 2, and because there are 4 numbers, you will need 2 sub-lists. When interating through the original list to fill the sub-lists it should go [[],[]] -> [[1],[]] -> [[1],[2]] -> [[1, 3], [2]] -> [[1, 3], [2, 4]]).