Create a function, that will for a given a, b, c, do the following:
a to itself b times.c.abcmath(42, 5, 10) ➞ False
# 42+42 = 84,84+84 = 168,168+168 = 336,336+336 = 672, 672+672 = 1344
# 1344 is not divisible by 10
abcmath(5, 2, 1) ➞ True
abcmath(1, 2, 3) ➞ False
c", means that if you divide the result and c, you will get an integer (5, and not 4.5314).